SRM550 Div2 Easy(250)
originalWordをfinalWordに書き換えて、残り回数が偶数なら可能。
#include <string> using namespace std; class EasyConversionMachine{public: string isItPossible( string originalWord, string finalWord, int k ) { for ( int i=0; i<(int)originalWord.length(); i++ ) if ( originalWord[i]!=finalWord[i] ) k--; if ( k>=0 && k%2==0 ) return "POSSIBLE"; else return "IMPOSSIBLE"; }};